{"scoreShow":"Check","tryAgain":"Retry","scoreExplanation":"Correct answers give +1 point. Incorrect answers give -1 point. The lowest possible score is 0.","question":{"settings":{"size":{"width":620,"height":620}},"task":{"elements":[{"x":1.6129032258064515,"y":0,"width":37.125,"height":5,"dropZones":[],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

Setup and solve this mole-to-mole stoichiometry problem.<\/p>\n\n

<\/p>\n\n

How many moles of carbon dioxide will be produced by the reaction of 6.7 moles of glucose according to this reaction?<\/p>\n\n

<\/p>\n\n

glucose + 6 oxygen --> 6 carbon dioxide + 6 water<\/strong><\/p>\n"},"subContentId":"249c7a53-861d-48af-ad41-f7676a18f8d9","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":false},{"x":27.419354838709676,"y":43.136764034148186,"width":14,"height":4.5,"dropZones":[],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

___________________ =<\/p>\n"},"subContentId":"5cf6c36b-2a60-413b-95bc-67f0400898f9","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":false},{"x":4.838709677419355,"y":68.62745098039215,"width":4.201820515441894,"height":4.201820515441894,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

6.7 mol glucose<\/p>\n"},"subContentId":"7dbb5d98-e865-431c-8ef8-84b8d4f77b52","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true},{"x":20.967741935483872,"y":68.62745098039215,"width":4.201822757720947,"height":4.201825,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

6 mol oxygen<\/p>\n"},"subContentId":"7d86f2bc-4d48-4a54-8663-6e8d7bd42cc8","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true},{"x":38.70967741935484,"y":68.62745098039215,"width":4.201822757720947,"height":4.201825,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

1 mol glucose<\/p>\n"},"subContentId":"70083932-16be-4a5e-a913-48a4b4086ad7","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true},{"x":56.45161290322581,"y":68.62745098039215,"width":4.201822757720947,"height":4.201822757720947,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

6 mol carbon dixoide<\/p>\n"},"subContentId":"e38c65b7-c0ab-487b-9137-4b8a477ebb3c","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true},{"x":72.58064516129032,"y":68.62745098039215,"width":4.201822757720947,"height":4.201822757720947,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

6 mol water<\/p>\n"},"subContentId":"3c224ab4-eff7-4c22-a842-d30004d39d81","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true},{"x":4.838709677419355,"y":84.31372549019608,"width":4.201822757720947,"height":4.201822757720947,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

40.2 mol carbon dioxide<\/p>\n"},"subContentId":"fed37a3e-6c55-4c53-810a-ca730e46912a","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true},{"x":20.967741935483872,"y":83.87096774193549,"width":4.201822757720947,"height":4.201822757720947,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

6.7 mol carbon dioxide<\/p>\n"},"subContentId":"dab967af-cfac-40d5-9550-aa14f726444e","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true},{"x":38.70967741935484,"y":83.87096774193549,"width":4.201822757720947,"height":4.201822757720947,"dropZones":["0","1","2","3"],"type":{"library":"H5P.AdvancedText 1.1","params":{"text":"

1.1 mol carbon dioxide<\/p>\n"},"subContentId":"9f2c329e-c7d7-4705-9de9-bcb87631e519","metadata":{"contentType":"Text","license":"U","title":"Untitled Text"}},"backgroundOpacity":100,"multiple":true}],"dropZones":[{"x":12.903225806451612,"y":41.1764705882353,"width":5,"height":5,"correctElements":["2"],"showLabel":false,"backgroundOpacity":100,"tipsAndFeedback":{"tip":""},"single":false,"autoAlign":true,"label":"

starting quantity<\/div>\n"},{"x":33.387096774193544,"y":29.411764705882355,"width":5,"height":5,"correctElements":["5"],"showLabel":false,"backgroundOpacity":100,"tipsAndFeedback":{"tip":""},"single":false,"autoAlign":true,"label":"
top ratio<\/div>\n"},{"x":33.87096774193548,"y":50.98039215686275,"width":5,"height":5,"correctElements":["4"],"showLabel":false,"backgroundOpacity":100,"tipsAndFeedback":{"tip":""},"single":false,"autoAlign":true,"label":"
bottom ratio<\/div>\n"},{"x":64.51612903225806,"y":40.32258064516129,"width":5,"height":5,"correctElements":["7"],"showLabel":false,"backgroundOpacity":100,"tipsAndFeedback":{"tip":""},"single":false,"autoAlign":true,"label":"
Answer<\/div>\n"}]}},"overallFeedback":[{"from":0,"to":100}],"behaviour":{"enableRetry":true,"enableCheckButton":true,"singlePoint":false,"applyPenalties":false,"enableScoreExplanation":true,"dropZoneHighlighting":"dragging","autoAlignSpacing":2,"enableFullScreen":false,"showScorePoints":true,"showTitle":true},"grabbablePrefix":"Grabbable {num} of {total}.","grabbableSuffix":"Placed in dropzone {num}.","dropzonePrefix":"Dropzone {num} of {total}.","noDropzone":"No dropzone.","tipLabel":"Show tip.","tipAvailable":"Tip available","correctAnswer":"Correct answer","wrongAnswer":"Wrong answer","feedbackHeader":"Feedback","scoreBarLabel":"You got :num out of :total points","scoreExplanationButtonLabel":"Show score explanation","a11yCheck":"Check the answers. The responses will be marked as correct, incorrect, or unanswered.","a11yRetry":"Retry the task. Reset all responses and start the task over again.","localize":{"fullscreen":"Fullscreen","exitFullscreen":"Exit fullscreen"}}

Mole-to-mole ratio practice

Samantha Sullivan Sauer